Materials Required Per Unit (Km) Length of Track

Materials Required Per Unit(km) Length of Track

It is necessary to work out exactly the quantities of various materials required to lay track. Otherwise, the excess materials will have to be taken back and work will be delayed. In this article, we will discuss the number of rails, sleepers, fish plates, fish bolts, dog spikes, and bearing plates required for each kilometer of track length.

1. Number of rails per km of track

= $\frac{100}{length\; of \; rail }\times 2$

In case of 12.80 m length of the rail

The number of rails will be required for each kilometer(per km) of track length

= $\frac{100}{12.80}\times 2$ =156.25. say 157 nos.

2. Number of sleepers per km of track length

= $\frac{no.\; of \; rails\; per \; km}{2}\times (n+x)$

Where (n+x) is the expression for sleeper density.

if x = 3, then the approximate number of sleepers required in the above case of 12.80 m rail would be equal to

$\frac{157}{2}\times \left ( 12.80+ 3 \right )$ = 1240.3 say 1241 nos.

3. Number of fish plates per km of track length

= 2 × number of rails per km(kilometer) of track

= 2 × 157 = 314 nos.

4. Number of fish bolts per km of track

= 4 × number of rails per km of track length

Then, the number of fish bolts will be required for each kilometer(per km) of track length

= 4 × 157 = 628

5. Number of bearing plates per km of track

= 2 × number of sleepers per km of track

The number of rails will be required for each kilometer(per km) of track length

= 2 × 1241 = 2482 nos.

6. Number of dog spikes per km of track

= 4 × number of sleepers per km of track length

Then, the number of dog spikes will be required for each kilometer(per km) of track length

= 4 × 1241 = 4964 nos.

Read Also:

Types of Railway Sleepers

TYPES OF RAILS

5 Major Cross Sectional Elements of a Railway Track