Numerical Example For Error Due To Wrong Measuring Scale – Survey Engineering29th April 2019
Numerical Example For Error Due To Wrong Measuring Scale
Following numerical example shows that how to calculate correct length and area, if errors occur due to wrong measuring scale:
A surveyor measured the distance between two points marked on the plan drawn to a scale of 1cm = lm (R.F. = 1: 100) and found it to be 60m. Later he detected that he used a wrong scale of 1 cm = 50 cm (R.F. = 1: 50) for the measurement.
(a) Determine the correct length.
(b) What would be the correct area if the measured area is 70 m²?
a. Correct length = (R.F. of the wrong scale/R.F. of the correct scale) ⨯ measured length = [(1/50)/(1/100)] ⨯ 60 = 120m.
b. Correct area = (R.F. of the wrong scale/R.F. of the correct scale)² ⨯ measured area = [(1/50)/(1/100)]² ⨯ 70 = 280 m².