How to Calculate Annual Runoff?
Mathematical Problem:
For a catchment in M.P., India, the mean monthly rainfall and temperatures are given. Calculate the annual runoff by Khosla’s formula.
Month | Jan | Feb | Mar | Apr | May | June | July | Aug | Sep | Oct | Nov | Dec |
Temp (°C) | 12 | 16 | 21 | 27 | 31 | 34 | 31 | 29 | 28 | 29 | 19 | 14 |
Rainfall | 4 | 4 | 2 | 0 | 2 | 12 | 32 | 29 | 16 | 2 | 1 | 2 |
Solution:
In Khosla’s formula,
Rm = Pm – Lm
Where,
- Rm = Monthly runoff
- Pm = Monthly rainfall in cm
- Lm = (0.48 × T) Or Pm whichever is less.
- T = Monthly temperature in degrees.
1. For January month
Lm = (0.48 × 12) = 5.76
So, 5.76 is greater than the corresponding Pm = 4.
So, the value of Lm will be taken as 4.
Now,
Rm = (Pm – Lm) = (4 – 4) = 0
2. For July month
Lm = (0.48 × 31) = 14.88
So, 14.88 is less than the corresponding value of Pm = 32
So, we will take the value of Lm = 14.9
Now,
Rm = (Pm – Lm) = (32 – 14.88) = 17.1
I think you can able to solve the rest of the months by using the above method.
Month | Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec |
Rainfall (Pm) | 4 | 4 | 2 | 0 | 2 | 12 | 32 | 29 | 16 | 2 | 1 | 2 |
Temp (°C) | 12 | 16 | 21 | 27 | 31 | 34 | 31 | 29 | 28 | 29 | 19 | 14 |
Lm | 4 | 4 | 2 | 0 | 2 | 12 | 14.9 | 13.9 | 13.4 | 2 | 1 | 2 |
Rm | 0 | 0 | 0 | 0 | 0 | 0 | 17.1 | 15.1 | 2.6 | 0 | 0 | 0 |
So, the total annual runoff = ( 17.1 + 15.1 + 2.6) = 34.8 in cm.
Read More: