Month: October 2020

# Analysis and Design of Rigid Pavement – MCQ

## Analysis and Design of Rigid Pavement – MCQ

1. What is the maximum spacing of contraction joints in the case of rigid pavement?

a) 5.5 m
b) 5 m
c) 4.5 m
d) 3.5 m

c) 4.5 m

2. In the case of rigid pavements, the role of an expansion joint is to

a) Reduce the warping stresses.
b) Reduce shrinkage stress.
c) Maintain stress due to expansion.
d) None of these.

a) Reduce the warping stresses

3. When do we expect the Critical combination of stress at edge = Load stress + Warping stress – Frictional stress.

a) During summer mid-day.
b) During summer midnight.
c) During winter mid-day.
d) During winter midnight.

a) During summer mid-day.

4. What is the critical combination of stresses at edge during winter mid-day

a) Load stress + Warping stress + Friction stress.
b) Load stress + Warping stress.
c) Load stress – Warping stress.
d) Load stress + Warping stress – Friction stress.

a) Load stress + Warping stress + Friction stress

5. Dowel bar in concrete pavement is placed in which direction

a) Along the direction of the traffic.
b) Along the perpendicular direction of the traffic.
c) Along 45 to the direction of traffic.
d) None of these.

a) Along the direction of the traffic

6. What are the purposes of providing dowel bar in CC pavement

a) To transfer the load from one slab to another.
b) To keep the two slab in same height.
c) Both (a) and (b).

c) Both (a) and (b).

7. The joints which are parallel to the center-line of the road, are known as

a) Expansion joints.
b) Transverse joints.
c) Longitudinal joints.
d) None of the above.

c) Longitudinal joints

8. Falling weight deflectometer(FWD) is an equipment are used to measure

a) Surface roughness of a pavement.
b) Structural capacity of the pavement.
c) Curvature of a horizontal curve.
d) Impact value of road aggregate.

b) Structural capacity of the pavement

9. If a slab cools uniformly then the crank due to temperature stress will develop at

a) Center
b) Near Edge
c) Corners
d) Near edges and corners

d) Near edges and corners

10. The gap width for the expansion joint is in between

a) 10 mm to 15 mm.
b) 20 mm to 25 mm.
c) 30 mm to 35 mm.
d) 40 mm to 45 mm.

b) 20 mm to 25 mm

Flexible Pavement – MCQ

Principle of Pavement Design – MCQ

# How to Calculate Weight of Steel Bar dia of 8, 10, 12, 16, 20, 25, 28, 40 mm

## How to Calculate Weight of Steel Bar Used in RCC Structure

There are two ways to calculate the weight of the steel bar used in RCC work. You can calculate the weight either using the formula or following the general procedure. The formula will help you to get quick results. So, it will save your time. But the general way will help you to know the exact way of calculation.

### Calculate the Weight of the Steel bar by Using Formula

The weight of the steel bar can be calculated by using the (d2 ÷ 162) formula, where ‘d’ is the dia of a bar in mm.

Example 1: Let’s assume the dia of a bar is 12 mm.

So, the weight of the bar will be = (122 ÷ 162) = 0.888 kg/m.

Example 2: Let’s assume the dia of a bar is 12 mm and the length is 3 m.

So, the weight of bar will be = (122 ÷ 162) × 3 = 0.888 × 3 = 2.664 kg.

Example 3: Let’s assume the dia of a bar is 16 mm and the length is 4.5 m.

Therefore, the weight of bar will be = (162 ÷ 162) × 4.5 = 1.58 × 4.5 = 7.11 kg.

Example 4: Let’s assume the dia of a bar is 20 mm and the length is 10 ft.

The length of the bar is given in feet. So, we need to convert it in a meter. 10 ft = 3.048 m. [Note: 1ft = 0.3048 m]

The weight of the bar will be = (202 ÷ 162) × 3.048 = 2.469 × 3.048 = 7.52 kg

### Calculate the Weight of the Bar by Following General Procedure:

In this method, we need to calculate the volume of the bar. We know, a steel bar that looks like a solid cylinder

The volume of the steel bar(V) = A × h = πr2 × h.

Where ‘A’ is the area of the base, ‘h’ is the height/length of the bar, and r is the radius of the bar. [ r = d/2, where, ‘d’ is the dia of the bar].

We know, the density of the bar is (γ) = 7850 kg/m3

Therefore, the weight of steel bar = Volume of the bar × Density of bar = πr2h × γ.

Example 1: Let’s assume the dia of a bar is 8 mm, and the length is 3 m.

• r = d/2 = 8/2 = 4 mm.
• h = 3 m.
• A = πr2 = π(4)2 = 50.26 mm2 = 5.026 × 10-5 m2.
• V = A × h = 5.026 × 10-5 × 3 = 1.507 × 10-4 m3.

The weight of the bar = V × γ = 1.507 × 10-4 × 7850 =1.18 kg.

Example 2: Let’s assume the dia of the bar is 12 mm and the length is 3 m.

• r = d/2 = 12/2 = 6 mm.
• h = 3 m.
• A = πr2 = π(6)2 = 113.097 mm2 = 1.1309 × 10-4 m2.
• V = A × h = 1.1309 × 10-4 × 3 = 3.3929 × 10-4 m3.

The weight of the bar = V × γ = 3.3929 × 10-4 × 7850 = 2.66 kg.

How to Calculate Quantity of Cement, Sand & Aggregate in M20

Composite Steel-Concrete Floor and Deck System

# Construction Equipment – MCQ

## Construction Equipment – MCQ

1. Hot-mix plant is used for

a) Cement concrete pavement Construction.
b) Bituminous pavement construction.
d) All the above.

b) Bituminous pavement construction.

2. Scraper is used for

a) Scraping of soils.
b) Excavation only.
c) Excavation, transporting, and dumping of soil.
d) None of these.

b) Excavation only.

3. Dump tracks are

a) Self-propelled hauling equipment.
b) Towed hauling equipment.
c) Self-propelled excavating equipment.
d) None of these.

a) Self-propelled hauling equipment.

4. Size of the power shovel is governed by

a) Size of the dipper.
b) Size of tyres.
c) Capacity of the engine.
d) All the above.

a) Size of the dipper.

5. Sheep foot roller is used for compacting

a) Granular soil.
b) Non-plastic silts.
c) Fine sands.
d) Clay soil.

d) Clay soil.

6. A dum track is also called a _

a) Dumper
b) Crawler
c) Bulldozer

a) Dumper

7. The primary purpose of a tractor is

a) Excavating
c) Filling
d) None of these

8. Which types of tractor have a higher speed

a) Wheel Tractor
b) Crawler tractor

a) Wheel Tractor

9. What are the advantages of a four-wheeler tractor over two wheeler tractor

a) Easy to maintain.
b) Less rolling resistance.
c) Less tendency to bounce on rough roads.
d) All of these.

c) Less tendency to bounce on rough roads.

a) Steel
b) Wooden
c) Fiber
d) Iron

b) Wooden

11. The formula used to determine the number of scrapers that a tractor may serve is

a) N = Ts/Tp
b) N = Tp/Ts
c) N = 2Ts/Tp
d) N = 0.5Ts/Tp

Where, N = Number of scrapers served, Ts = Cycle time for scraper, Tp = Cycle time for pusher tractor.

a) N = Ts/Tp

Stone Masonry – MCQ

Types of Shovels

# Find the cement bags, sand(CFT) & aggregate in M20, M15 concrete

## Calculate the Quantity of Cement, Sand & Aggregate in M20 Concrete

First of all, I want to assure you that it is very easy to determine the quantity of sand, cement, and aggregate in M20, M15, and M10 Concrete. So take a look carefully and will easily be understood.

Let’s take some examples,

Example: 1

Let’s assume that the volume of total concrete(wet concrete) required for a particular work is 2 m3. Now find out the quantity of cement, sand, and aggregate.

Solution:

In the case of M 20 concrete, the ratio of cement, sand, and aggregate is 1: 1.5: 3.

Dry volume of concrete = wet volume of concrete × 1.54 [ You can take this factor from 1.54 to 1.57 ]

Hence, the dry volume of concrete is = 2 × 1.54 = 3.08 m3

The required quantity of cement is = (Cement ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{1}{(1 + 1.5 + 3)} \times 3.08$ = 0.56 m3

### How do you calculate cement in bags?

First of all, we need to calculate it in kg. We know that the density of cement is 1440 kg/ m3. Therefore, 0.56 m3 cement means 0.56 × 1440 = 806.4 kg cement.

In general, each bag of cement weight is 50 kg.

So, the required number of cement bags are = 806.4 ÷ 50 = 16.12 ≈ 17 No.s.

Quantity of sand required = ( Sand ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{1.5}{(1 + 1.5 + 3)} \times 3.08$ = 0.84 m3

### How do you calculate sand in CFT?

Our total quantity of sand is 0.84 in m3, but in CFT(cubic feet) it will be ( 0.84 × 35.31) = 29.66 ≈ 30 CFT( cubic feet) [ Note: 1 m3 = 35.31 CFT or cubic feet ]

Quantity of aggregate is = ( Aggregate ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{3}{(1 + 1.5 + 3)} \times 3.08$ = 1.68 m3.

### How do you calculate aggregates in CFT?

We know, 1 m3 is equal to 35.31 CFT. Therefore, 1.68 m3 aggregate means 1.68 × 35.31 = 59.32 ≈ 60 CFT.

Example: 2

A section of footing is given below. Find out the quantity of cement sand and aggregates required for this footing.

Solution:

At first, we need to calculate the total volume of concrete required for this footing. The total volume of concrete is equal to the total volume of footing.

So, the total volume of concrete is = 1 × 7 × 6 = 42 cubic feet.

Dry volume of concrete will be = 42 × 1.54 = 64.68 cubic feet.

In the case of M20 concrete,

The Quantity of cement required for this footing is = $\frac{1}{(1 + 1.5 + 3)} \times 64.68$ = 11.76 cubic feet. Or, 0.33 in m3 [ Note: 1 m3 = 35.31 CFT or cubic feet]

The weight of cement = 0.33 × 1440 = 475.2 kg. Or, 475.2/50 = 9.50 ≈ 10 No.s bags.

Quantity of sand required = $\frac{1.5}{(1 + 1.5 + 3)} \times 64.68$ = 17.64 cubic feet or CFT .

The Quantity of aggregate required = $\frac{3}{(1 + 1.5 + 3)} \times 64.68$ = 35.25 CFT.

## Calculate the Quantity of Cement, Sand & Aggregate in M15 Concrete.

Now, we will calculate the quantity of cement and aggregate in M15 Concrete. Let’s take an example,

Example:

Let’s assume that the volume of total concrete(wet concrete) required for a particular work is 1 m3. Now find out the quantity of cement, sand, and aggregate.

Solution:

In the case of M15 concrete, the ratio of cement, sand, and aggregate is 1: 2: 4.

Dry volume of concrete = wet volume of concrete × 1.54

Hence, the dry volume of concrete is = 1 × 1.54 = 1.54 m3

The required quantity of cement is = (Cement ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{1}{(1 + 2+ 4)} \times 1.54$ = 0.22 m3

0.22 m3 cement means 0.22 × 1440 = 316.8 kg cement.

In general, each bag of cement weight is 50 kg.

So, the required number of cement bags are = 316.8 ÷ 50 = 6.33 ≈ 7 No.s.

Quantity of sand required = ( Sand ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{2}{(1 + 2 + 4)} \times 1.54$ = 0.44 m3

Our total quantity of sand is 0.44 in m3, but in CFT(cubic feet) it will be ( 0.44 × 35.31) = 15.53 ≈ 16 CFT( cubic feet) [ Note: 1 m3 = 35.31 CFT or cubic feet ]

Quantity of aggregate is = ( Aggregate ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{4}{(1 + 2 + 4)} \times 1.54$ = 0.88 m3.

We know, 1 m3 is equal to 35.31 CFT. Therefore, 0.88 m3 aggregate means 0.88 × 35.31 = 31.07 ≈ 32 CFT.

## Calculate the Quantity of Cement, Sand & Aggregate in M10 Concrete.

Now, we will calculate the quantity of cement and aggregate in M10 Concrete. Let’s take an example,

Example:

Let’s assume that the volume of total concrete(wet concrete) required for a particular job is 3 m3. Now find out the quantity of cement, sand, and aggregate.

Solution:

In the case of M10 concrete, the ratio of cement, sand, and aggregate is 1: 3: 6.

Dry volume of concrete = wet volume of concrete × 1.54

Hence, the dry volume of concrete is = 3 × 1.54 = 4.62 m3

The required quantity of cement is = (Cement ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{1}{(1 + 3+ 6)} \times 4.62$ = 0.462m3

0.22 m3 cement means 0.462× 1440 = 665.28 kg cement.

In general, each bag of cement weight is 50 kg.

So, the required number of cement bags are = 665.28 ÷ 50 = 13.3 ≈ 14 No.s.

Quantity of sand required = ( Sand ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{3}{(1 + 3 + 6)} \times 4.62$ = 1.386 m3

Our total quantity of sand is 1.386 m3 , but in CFT(cubic feet) it will be ( 1.386 × 35.31) = 48.93 ≈ 49 CFT( cubic feet) [ Note: 1 m3 = 35.31 CFT or cubic feet ]

Quantity of aggregate is = ( Aggregate ratio ÷ Sum of all ratio) × Total volume of concrete = $\frac{6}{(1 + 3 + 6)} \times 4.62$ = 2.77 m3.

We know, 1 m3 is equal to 35.31 CFT. Therefore, 2.77 m3 aggregate means 2.77 × 35.31 = 97.8 ≈ 98 CFT.

Types of Aggregates

Different Types of Cement Tests

# Road Geometric – MCQ || Highway Engineering

1. A portion of the roadway used by the pedal bicyclist only is called

a) Cycle street
b) Cycle track
d) Carriageway

b) Cycle track

2. As per IRC recommendation, which is the following camber used for cement concrete road

a) 1 in 50
b) 1 in 45
c) 1 in 24
d) 1 in 20

a) 1 in 50

3. The highest point on the carriageway is termed as

a) Camber
c) String
d) Crown

d) Crown

4. The recommended safe coefficient of friction is

a) 1.5
b) 0.15
c) 1/2
d) 2/3

b) 0.15

5. The land width required for national and state highways in the built-up area should be

a) 30 m to 60 m
b) 50 m 70 m
c) 10 m 16 m
d) None

a) 30 m to 60 m

This value only for plain and rolling terrain

6. What is the minimum width of shoulders provided in national highway?

a) 1 m
b) 1.5 m
c) 2 m
d) 2.5 m

d) 2.5 m

7. As per IRC recommendation, the slope of the earth in cutting should be

a) 1: 2
b) 1: 1
c) 1: 4
d) 2: 3

b) 1 : 1

8. The land width required for major district roads in open areas should be

a) 30 m to 60 m
b) 25 m 30 m
c) 15 m 20 m
d) None

b) 25 m 30 m

9. The portion of the road surface which is used by vehicular traffic is known as

a) Carriageway
b) Shoulder
c) Expressway
d) All the above.

a) Carriage way

10. Summit curve is a type of ___ curve.

Vertical

5 Components of a City Road

# Stone Masonry – MCQ || Building Construction

## Stone Masonry – MCQ

1. When a construction made by using only stones is known as

a) Brick masonry
b) Stone masonry
c) Brick and stone masonry
d) None

b) Stone masonry

2. Why mortars are used in stone masonry work

a) To keep them in position.
b) To make a joint.
c) To fill up hollow spaces.
d) All the above.

d) All the above.

3. In case of large hollows, which component is added in the mortar to impart the strength to the filling

a) Stone chippings
b) Small-sized aggregate
c) Both (a) and (b)
d) More water

c) Both (a) and (b)

4. In the case of cement-lime mortar, which component acts as predominant binding materials

a) Lime
b) Cement
c) Both (a) and (b)
d) None of these

b) Cement

5. In the case of lime-cement mortar, which component acts as predominant binding materials

a) Lime
b) Cement
c) Both (a) and (b)
d) None of these

a) Lime

6. In stone masonry, a horizontal layer of stones is known as

a) Bed
b) Bond
c) Stretcher
d) Course

d) Course

7. In lower surface of stones in which they rest is known as

a) Face
b) Back
c) Backing
d) Bed

d) Bed

8. When stones are placed right across the wall at a regular intervals is known as

a) Backing
b) Hearting
c) Through stone
d) None of these.

c) Through stone

9. Which statement is false

Stone is _____

a) Stronger than brick.
b) More durable than brick.
c) More weather resisting than brick.
d) More resistant to fire than brick.

d) More resistant to fire than brick.

Stone – MCQ

Rocks – MCQ

Qualities of Good Building Stone

18 Comparison Between Stone Masonry and Brick Masonry

# Stone – MCQ || Building Materials

## Stone – MCQ

1. In India, which of the following famous building made by stones

a) Taj Mahal
b) Red Fort
c) Parliament House
d) Jama Masjid
e) All of these

e) All of these

2. The natural bed of stones can occur in case of only

a) Sedimentary rocks
b) Metamorphic rocks
c) Igneous rocks

a) Sedimentary rocks

3. Crushing strength of a good structural stone should be more than

a) 50 N/ mm2
b) 65 N/ mm2
c) 100 N/ mm2
d) 200 N/ mm2

c) 100 N/ mm2

4. The value of the crushing strength of limestone is around

a) 35 N/ mm2
b) 44 N/ mm2
c) 54 N/ mm2
d) 150 N/ mm2

c) 54 N/ mm2

5. Which of the following factors affects the durability of a stone?

a) Heat and cold
b) High-speed wind
c) Dissolve gases in rains
d) All of these

d) All of these

6. Which value shows a stone of poor quality toughness?

a) Less than 13
b) More than 13
c) Less than 19
d) more than 19

a) Less than 13

7. For a good building stone, the value of wear in case of attrition test should be

a) less than 3 %
b) more than 3 %
c) more than 5 %
d) None

a) less than 3 %

8. A good building stone should possess specific gravity

a) Greater than 1.5
b) Greater than 2.7
b) Greater than 1
c) Less than 2.7

b) Greater than 2.7

9. Which statement is true

a) Stone is much more stronger than Brick.
b) Stone is somewhat stronger than Brick.
c) Stone is not stronger than Brick.

a) Stone is much more stronger than Brick.

Rocks – MCQ

Weathering of Rocks – MCQ

Types of Joints in Stone Masonry

Stone Masonry – MCQ

# Rocks – MCQ || Building Material & Geology

## Rocks – MCQ

1. Which rocks are formed due to the cooling of magma

a) Igneous rocks.
b) Sedimentary rocks.
c) Metamorphic rocks.
d) None.

a) Igneous rocks.

2. Plutonic rock is a type of

a) Igneous rock.
b) Sedimentary rock.
c) Metamorphic rock.
d) None.

a) Igneous rock.

3. Which rocks are formed due to the cooling of magma at a relatively shallow depth

a) Plutonic rocks.
b) Hypabyssal rocks.
c) Volcanic rocks.
d) Metamorphic rocks.

b) Hypabyssal rocks.

4. The rocks which are formed due to the pouring of magma at the earth’s surface

a) Plutonic rocks.
b) Hypabyssal rocks.
c) Volcanic rocks.
d) Metamorphic rocks.

c) Volcanic rocks.

5. The rocks which are formed due to change in the character of the pre-existing rocks are

a) Igneous rocks.
b) Sedimentary rocks.
c) Metamorphic rocks.
d) Plutonic rocks.

c) Metamorphic rocks.

6. Clay is the predominant constituent of ___ rocks.

a) Siliceous.
b) Argillaceous.
c) Calcareous.

b) Argillaceous.

7. Which is the predominant constituent of calcareous rocks

a) Silica.
b) Clay.
c) Calcium carbonate.
d) None.

c) Calcium carbonate.

8. Which is the predominant constituent of Siliceous rocks.

a) Silica.
b) Clay.
c) Calcium carbonate.
d) None.

a) Silica.

9. Calcareous rocks are

a) Limestone.
b) Marbel.
c) Granites.
d) Both (a) and (b).

d) Both (a) and (b).

10. Example of Argillaceous rocks is

a) Limestone.
b) Slates.
c) Granites.
c) Quartzites.

b) Slates.

11. Example of Siliceous rocks is

a) Limestone.
b) Laterites.
c) Marble.
c) Quartzites.

c) Quartzites.

12. The definite shape of the rock is

a) Rectangular.
b) Angular.
c) Round.
d) None.

d) None.

The rocks has no definite shape.

13. The rocks which contain only one mineral is known as

a) Polyminerallic rocks.
b) Monomineralic rocks.
c) Tripomineralic rock.
d) None.

b) Monomineralic rocks.

14. Which rocks have a tendency to split in a definite direction only

a) Unstratified rocks.
b) Stratified rocks.
c) Foliated rocks.
d) None of these.

c) Foliated rocks.

Partition Walls

Weathering of Rocks – MCQ

Joints and Faults in Rocks

# Qualities of Good Building Stone – Building Materials

## Qualities of Good Building Stone

Stone is a very common building material where it is available on a large scale. The stones are mostly used for foundation work, outer walls, road construction, and dam construction.

The stonework is not as easy as brickwork, it has several drawbacks. It is necessary to check their quality first before using stones in building works. Following are some properties or characteristics or qualities of good building stones.

### 1. Appearance

The stones that are to be used for the work of the face should have a good appearance. They should be able to retain their uniform color and appearance for a long time.

### 2. Colour

Color is an indicator of good building stones. Uniform color is always desirable for good building stones. It is desirable to use light-colored stones at the face work and also for exposed positions.

### 3. Crushing Strength

The crushing strength of a good building stone should be higher than 100 N /mm2. The crushing strength values of some of the stones are as given here.

### 4. Dressing

The stones quarried from quarries cannot be used directly for masonry work as they are quite irregular. It needs to cut or dressed in usable sizes and shapes by using suitable tools. This process is known as the dressing of stones. So, a good building stone should be such that it can be easily carved, cut, dressed, or moulded.

The dressing of stones is an important factor from an economic point of view. If the dressing of stones is very difficult and costly, then its use in construction work should be avoided as much as possible. Otherwise, labor costs will be increased which will increase the overall cost of construction.

### 5. Hardness

The coefficient of hardness for the stones which are used for road construction must be more than 17. The coefficient of hardness below 14 shows a stone of poor hardness. If the coefficient of hardness lies between 17 to 14, then it is said to be medium hardness.

### 6. Toughness Index

A good building stone should be tough enough. To find out the toughness of a stone, an impact test is carried out. If the value of the toughness index is above 19, the toughness of the stone is said to be high, and it indicates the quality of the stone is good.

When this value lies between 13 to 19, is said to be moderately tough. If this value is less than 13, the stone is said to be poor-tough, and it indicates the quality of the stone is bad.

### 7. Percentage of wear

In the attrition test, if the value of wear comes to more than 3%, the stone is unsatisfactory. For a good building stone, the value of wear should not be more than 3%.

### 8. Specific gravity

The specific gravity can help determine the quality and durability of stones for various applications. The specific gravity of stones can vary depending on the type of stone. Here are some approximate specific gravity values for commonly used stones in construction:

• Granite: 2.63 – 2.75
• Limestone: 2.3 – 2.7
• Marble: 2.65 – 2.80
• Slate: 2.7 – 2.8
• Quartzite: 2.65 – 2.80

For good building stones, the specific gravity should not be less than 2.7. The higher specific gravity of the stones indicates greater compactness, higher durability, and less porosity. For constructing heavy structures like dams, retaining walls, etc. heavier stones should be used.

### 9. Seasoning of Stones

Proper seasoning of stones helps improve the quality and durability of the stone, making it suitable for various applications. The quarried stones contain moisture(quarry sap), and the presence of quarry sap in the stones helps in the process of stone dressing. After shaping the stones, they must be properly seasoned, i.e. dried(remove quarry sap), before being used in construction. In order to remove quarry sap from the stone, it should be kept in the open air for at least 6 to 18 months from the date of the quarrying.

### 10. Resistance to fire

When it comes to using stones for constructing houses, the fire resistance property of stones should be good enough. Stones naturally possess qualities that allow them to withstand high temperatures and impede the spread of flames.

It’s important to note that the fire resistance of stones can vary depending on factors such as thickness, surface treatment, and types of stones. A good building stone should be such that it can resist high temperatures, sudden cooling, linear expansion of composing minerals, etc.

15 Important Points to be Considered During Construction of Stone Masonry

10 Types of Joints in Stone Masonry

# Permanent Way – MCQ || Railway Engineering ||

## Permanent Way – MCQ

1. Permanent track is regarded to be

a) Semi elastic in nature.
b) Elastic in nature.
c) Rigid in nature.
d) Semi-rigid in nature.

a) Semi elastic in nature

2. The track should be constructed and maintained keeping the requirement of a permanent way to achieve

a) High speed.
b) Better riding quality.
c) Less future maintenance.
d) All the above.

d) All the above.

3. Gauge of railway track is

a) The clear distance between inner faces of two track rails.
b) The distance between outer faces of two track rails.
c) The distance between inner face of one rail and outer face of another rail of the track.
d) None of the above.

a) The clear distance between inner faces of two track rails.

4. In India the width of narrow gauge is

a) 1.676 m.
b) 1.0 m.
c) 0.762 m.
d) 0.610 m.

c) 0.762 m.

5. The selection of a particular gauge depends upon

a) Cost of construction.
b) Volume and nature of traffic.
c) Speed of movement.
d) All the above.

d) All the above.

6. On curved tracks, superelevation is maintained by __ and the formation is levelled.

a) Sleepers.
b) Ballast.
c) Soil.
d) Rails.

b) Ballast.

7. The combination of rails, fitted on sleepers and resting on ballast and subgrade is called ____

a) Right of way.
b) Permanent way.
c) Carriageway.
d) None.

b) Permanent way

8. Wheels of trains are coned at a slope of _____.

a) 1 in 10
b) 1 in 15
c) 1 in 20
d) 1 in 30

c) 1 in 20

Wheels of trains are coned at a slope of 1 in 20.

9. Which are the components of permanent way

b) Ballast
c) Rails
d) Fixture
e) All the above
f) Option (a), (b) and (c), but not (d).

e) All the above

10. In U.K the width of narrow gauge is

a) 1.676 m
b) 1.0 m
c) 0.762 m
d) 0.610 m

c) 0.762 m

What is the Permanent way In Railway

Railway Ballast – MCQ

Rails – MCQ