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Relation Between Dry Unit Weight, Specific Gravity, Percentage of Air Voids and Water Content

Posted on 19th April 202011th March 2022 By Malay Sautya

Relation Between Dry Unit Weight, Specific Gravity, Percentage of Air Voids and Water Content

In this article, we shall make the formula or relation between the dry unit weight(\gamma _{d}), specific gravity(G), percentage of air voids and water content(w).

[Note: Dry unit weight means dry density]

Relation Between Dry Unit Weight, Specific Gravity, Percentage of Air Voids and Water Content

Soil three-phase diagram is shown in the above picture. From this diagram, we can write,

Total Volume = Volume of solids ( V_{s} )+ Volume of water ( V_{w} ) + Volume of air ( V_{a} )

V = V_{s} + V_{w} + V_{a}
[Both sides divided by V]
Or, \frac{V}{V}= \frac{V_{s}}{V} + \frac{V_{w}}{V} + \frac{V_{a}}{V}

[We know,  \frac{V_{a}}{V} = n_{a} ]

Or, 1 = \frac{V_{s}}{V} + \frac{V_{w}}{V} + n_{a}
Or, 1 - n_{a} = \frac{V_{s}}{V} + \frac{V_{w}}{V}

[ We know,  \gamma_{s} = \frac{W_{s}}{V_{s}} , and Specific Gravity(G)  = \frac{\gamma_{s}}{\gamma_{w} } = \frac{W_{s}}{V_{s}\gamma_{w} } ]

[From this equation, G = \frac{W_{s}}{V_{s}\gamma_{w} }, we can write  V_{s} = \frac{W_{s}}{G\gamma _{w}} . Now, place the value of  V_{s} in the above equation.]

Or, 1 - n_{a} = \frac{W_{s}/G\gamma_{w}}{V} + \frac{W_{w}/\gamma _{w}}{V}

[We know, Density of solids(\gamma_{d}) = \frac{W_{s}}{V}]

Or, 1 - n_{a} = \frac{\gamma_{d}}{G\gamma_{w} } + \frac{wW_{s}/\gamma _{w}}{V}

Or, 1 - n_{a} = \frac{\gamma_{d}}{G\gamma_{w} } + \frac{w\gamma_{d} }{\gamma_{w} }

Or, 1 - n_{a} = \frac{\gamma_{d}}{\gamma_{w} }\left [ w + \frac{1}{G} \right ]
\gamma_{d} = \frac{(1 - n_{a})G \gamma_{w}}{1 + wG}

Read More:

Relation Between Dry unit Weight, Bulk unit Weight & Water Content

Relation Between Void Ratio, Water Content, Degree of Saturation & Specific Gravity

Relation Between Porosity and Void Ratio

soil

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